P1V1=nRT
P2V2=n'RT
(1) becomes
n=2*d'V1/M1;
P1V1=(2*d'V1/M1)*RT .................(2) {V1 gets cancelled}
P2V2=(d'V2/28)*RT.......................(3) {V2 gets cancelled}
taking (2)/(3):
P1/P2=(2/M1)/(1/28)
->2/4=56/M1
->M1=112g mol^(-1)
pm=drt
p1= 2
p2= 4 d1= 2d2
m=56
We know
PV=nRT ,
d1=d2,
P1×M1=P2×M2,
2×2m=4×28
m1=28 g mol^-1
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