at same temperature calculate the ratio of average velocity of a SO2 to ch4
Answer (1)
18th Sep, 2019
Hello Shahana
The answer would have the following steps.
The root mean square velocity of a gas is given by:
v(rms) = √[3kT/M]
For two different gases 1 and 2 with two molecular weights M1 and M2, we can find the ratio:
v1/v2 = √[3kT/M1] /√[3kT/M2]
This reduces to:
v1/v2 = √[M2/M1]
Notice this is equivalent to Graham's law. Just substitute:
v(CH4)/v(SO2) = √[64/16] = 2.
The methane molecules go twice as fast.
Hope it helps you.
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