At what point on the curve y=e^x is the tangent line parallel to the line y=2x?
Hello candidate,
By using the principle of parallel lines, we can know that it both the parallel lines have the same slope which is given by dy/dx of both the curves.
So, taking the derivative of both the curves we get e^x = 2, and show the value of x is equal to (log 2), and the value of Y is equal to 2 (log2).
So, the point is ( log2, 2 log2).
Hope it helps!!