at what temperature 25dm3 of oxygen at 283 k is heated to make its volume 30dm3
V1=25 dm3 T1=283k
V2=30 dm3 T2=?
According to Charles law
V2/V1 = T2/T1
30/25 = T2/283
T2 = 30×283/25
T2 = 339.6k
Hello
preetismita04
, From some research on internet I found that it is not such a difficult solution you can do it easily by the formula of Charles law which is V1/T1=V2/T2.
And the solution is:
T2=30*283/25
T2=339.6K
Hope you understand it and it will be helpful for you :)