By passing electric current , NaclO3 is converted into NaclO4 . How many moles of NaclO4 will be formed when 3 faradays of charge is passed through NaclO3 ?
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The balanced chemical equation for above question is-
NaClO3 + H2O -> NaClO4 + H2
The oxidation state of Cl atom in NaClO3 is +5 and the oxidation state of Cl atom in NaClO4 is +7. So, the net change in oxidation state = 7-5 = +2.
This show that 2 faradays of charge is required to get 1 mole of NaClO4.
So if 1 faradays of charge is passed through NaclO3 then (1/2) mole of NaClO4 obtained.
Then 3 faradays of charge is passed through NaclO3 then (1/2)x3 mole of NaClO4 obtained that is 1.5 mole NaClO4 is obtained.
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