Question : C1, C2 and C3 can do work alone in 10, 12, and 15 days respectively. All three of them began the work together but C2 left 2 days before the completion of the work. In how many days was the work completed?
Option 1: 3
Option 2: 7
Option 3: 5
Option 4: 4
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Correct Answer: 5
Solution : C1, C2 and C3 can do a work alone in 10,12 and 15 days, respectively. C1's 1 day's work = $\frac{1}{10}$ C2's 1 day's work = $\frac{1}{12}$ C3's 1 day's work = $\frac{1}{15}$ (C1 + C2 + C3)'s 1 day's work = $\frac{1}{10}+\frac{1}{12}+\frac{1}{15}=\frac{1}{4}$ So, they will complete the work in 4 days. C2 left 2 days before the completion of the work. So, remaining work = $1-\frac{1}{2}=\frac{1}{2}$ (C1 + C3)'s 1 day's work = $\frac{1}{10}+\frac{1}{15}=\frac{1}{6}$ C1 and C3 together will complete the remaining work in $\frac{\frac{1}{2}}{\frac{1}{6}}=3$ days Total days = 2 + 3 = 5 days Hence, the correct answer is 5.
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