calculate molarityof 0.450 N HCl
Answer (1)
22nd Sep, 2020
Dear student,
For solutions, concentration term normality (N) is used, which can be defined as " the number of equivalent of solute present in one litre (1000mL) solution ".
Now,
N = (number of gram equivalents of solute) / (volume of solution in litre)
Therefore,
N = ( weight (in gm) × 1000 ) / (E × V (inml) )
Where, E = equivalent weight = molar mass / n factor
And therefore, N = (MOLARITY) × ( n factor)
So, as the given concentration is 0.45N HCl , therefore the molarity (M) = NORMALITY / n factor
n factor of HCl = 1
So, Molarity of 0.45N HCl = 0.45/1 = 0.45 M
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