Question : Calculate the HCF of $\frac{12}{5},\frac{14}{15},$ and $\frac{16}{17}$.
Option 1: $\frac{4}{255}$
Option 2: $\frac{3}{255}$
Option 3: $\frac{2}{255}$
Option 4: $\frac{1}{255}$
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Correct Answer: $\frac{2}{255}$
Solution : The LCM of 5, 15, and 17 = 255 The HCF of 12, 14, and 16 = 2 $\therefore$ The HCF of $\frac{12}{5},\frac{14}{15},$ and $\frac{16}{17}=\frac{2}{255}$ Hence, the correct answer is $\frac{2}{255}$.
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