Calculate the mass of urea required in making 2.5kg of 00.25 molar aq solution
Answer (1)
Student Expert
19th Feb, 2019
Hi Aman Bajpai !
Here is the solution of your numerical problem :-
Given that
given 0.25 molal,
Means in 1 kg of water(Solvent) 0.25 mole of Urea is present
Means in 1 kg of water(Solvent) 0.25 X 60 = 15 g of Urea is present
in Solution(1 kg of water + 15g urea) , 15 g of Urea is present
in 1015 g Solution, 15 g of Urea is present
in 1 g Solution, 15/1015 g of Urea is present
in 2500 g Solution, (2500X15)/1015 g of Urea is present
in 2500 g Solution, 36.9 g of Urea is present
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