calculate the mole fraction of ethylene glycol C2H6O2 in a solution containing20%of C2H6O2 by mass.
Hello, I hope you are doing well
It is given in the question that a solution of ethylene glycol contains 20% of ethylene glycol by mass.
which means, in 100g of solution - 20g of ethylene glycol.
Molar mass of ethylene glycol - (12*2 + 1*6 + 16*2) = 62g/mol.
therefore, in 20g we have 20/62 = 0.32 mol.
Mole fraction of ethylene glycol = No of moles of ethylene glycol/ Total number of moles.
= 0.32/(0.32 + 4.44)
= 0.068
Hope this helps