1292 Views

calculate the mole fraction of ethylene glycol C2H6O2 in a solution containing20%of C2H6O2 by mass.


Krishna saa 8th Apr, 2022
Answer (1)
piyush singh 10th Apr, 2022

Hello, I hope you are doing well

It is given in the question that a solution of ethylene glycol contains 20% of ethylene glycol by mass.

which means, in 100g of solution -  20g of ethylene glycol.

Molar mass of ethylene glycol - (12*2  + 1*6 + 16*2) = 62g/mol.

therefore, in 20g we have 20/62 = 0.32 mol.

Mole fraction of ethylene glycol = No of moles of ethylene glycol/ Total number of moles.

= 0.32/(0.32 + 4.44)

= 0.068

Hope this helps


Related Questions

CLAT Current Affairs with GK ...
Apply
Stay updated with current affairs & check your preparation with the CLAT General Knowledge Mock Tests Ebook
CLAT English Language Mock Tests
Apply
Free Ebook - CLAT 2025 English Language questions with detailed solutions
ICFAI Business School-IBSAT 2024
Apply
9 IBS Campuses | Scholarships Worth Rs 10 CR
CLAT Legal Reasoning Mock Tests
Apply
Free Ebook - CLAT 2025 legal reasoning questions with detailed solutions
GIBS Business School Bangalor...
Apply
100% Placements with 220+ Companies
Great Lakes PGPM & PGDM 2025
Apply
Admissions Open | Globally Recognized by AACSB (US) & AMBA (UK) | 17.3 LPA Avg. CTC for PGPM 2024
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books