calculate the mole fraction of ethylene glycol (C2H6O2)&water in a solution containing 20 percent of C2H6O2 by mass.
Answer (1)
21st Sep, 2020
Hello !
As given in the question, a solution of ethylene glycol and water contains 20% of ethylene glycol by mass.
That is, in 100g of solution - 20g of ethylene glycol.
Molar mass of ethylene glycol - (12*2 + 1*6 + 16*2) = 62g/mol.
so, in 20g we have 20/62 = 0.32 mol.
remaining 80g contains water. Number of moles of water = 80/18 = 4.44 mol
Mole fraction of ethylene glycol = No of moles of ethylene glocal/ Total number of moles.
= 0.32/(0.32 + 4.44)
= 0.068 .
Mole fraction of water = 1-0.068 = 0.932
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