Can a student, who got 94.62 percentile in jee mains 2020,belongs to OBC, can get into NIT AP in ECE branch?
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Hi Paidikala,
You got 94.62 percentile in JEE main exam, your rank would be approximately in between 50000 to 54000. Also, Above is the range of your possible rank. The predicted rank may vary due to JEE Main tie breaker rules for the same score. Also, you can check your expected rank using the formula:
Rank = (100-percentile)*(No. of students appeared for the examination)/100
As the no. of students appeared for Paper 1 are 869010 , your rank will be around 54000. However as the no. of students in April changes, your rank will change according to that
On the basis of your percentile, the colleges you will get are:
Xavier institute of technology,Mumbai
SCOE Pune
IIIT Pune
IIST Indore
Jabalpur engineering college
You can also go through our college predictor to check which colleges you are eligible for through your JEE Mains score. The link for the college predictor is :
You will not get NIT AP in ECE branch. The cutoff goes for ECE in NIT branch are upto 22,000 rank.
Dear aspirant, according to your percentile score in JEE MAIN examination your expected rank is about 46,752. Your expected category rank is 12k. According to previous year cut off in ECE branch at NIT AP was ALL INDIA M(close-6876)&F(close-9165). For home state this was M(close-6035)&F(close-6955).
Still you need to wait Defoe your exact category rank because it is difficult at this point of time as we do not have data for no. Of OBC students appearing.
Thank you hope this helps you!
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