can anybody pls tell me minimum round 6 percentile to get top branches in NIT KUK . i am from haryana and my state quota and sc quota will apply . i know on the basis of rank i will get NIT KUK but still pls give me round 6 percentile for NIT kuk under state and sc quota.
Answer (1)
Student Expert
31st May, 2020
Hello,
Cut off is given in terms of closing rank and opening rank for each category and branch.In 2019 the round 6 cut off was follows for SC home state category for various branches
- EE: 5209
- Civil: 5581
- Production: 7231
- IT: 2004
- Computer: 1521
- Mechanical: 5432
- ECE: 3894
It is difficult to give the exact percentile.But according to the number of candidates appeared in JEE Main January 2020 session you need to score 90-95 percentile to get such rank as in 2019 round 6 cut off rank.But cut off changes in 2020 depending on number of candidates appeared, seats available in each branch etc.
Please try our JEE main knockout program
Comments (0)
Related Questions
Know More about
Trending Articles/News
