Can anyone give me the answer of this question of Physics of circular motion?
Hello Aspirant.
Since it's a frictionless surface, the total potential energy of the body will be converted to kinetic energy.
So, mgh=½mv^2
h=v^2/2g
Since the minimum velocity at the lowest point to complete the loop is √(5gr)
So, h= (5gD/2)/2g
Therefore the minimum height= 5/4D
Hope it helps.