Can anyone tell me what are the marks required to get 99 percentile
Hello Aspirant,
The calculation of the marks & rank would be difficult based on your percentile. You may calculate your expected rank by this formula
100 - your total percentile score is the percentage of people ahead of you. 874469 are the number of candidates appeared for Jan exam. So rank formula is (100 - your total score) X 869010 /100. If the number of candidates for April exam increased to 1200000 then your final rank shall be (100 - your total score) X 1200000/100
Using the formula
(100 - your total score) X 869010 /100
Your probable rank will be 8,690
As per previous year cutoff, You might have the chance to get National Institute of Technology Tiruchirappalli, National Institute of Technology Karnataka Surathkal, National Institute of Technology Warangal- Civil & Chemical, Motilal Nehru National Institute of Technology Allahabad Prayagraj, National Institute of Technology Rourkela- Mechanical, Civil, EEE Etc.
To know the other admission possibilities, You can use JEE Main College Predictor tool.
Good Luck!