Can I attempt JEE advanced with 82.8 percentile I'm a general category student
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Hello aspirant
Considering the total number of students to be 10 lakhs and using the below formula.
Rank= (total number of students -(percentile*0.01*number of students))
Your rank comes out to be 172000 .
This is sufficient to qualify for jee advance .
All the best.
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