can I get LNMIIT Jaipur in 95 percentile in jee mains 2020 January attempt?
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Answer (1)
5th Jun, 2020
Hello there,
According to the formula, [100-95*869010/100], your All India Rank is 43450 approximately, where 869010 is the total number of students who appeared in JEE Main Jan session. Since you haven't mentioned your category, I'm assuming that you are from the general category.
Now, you haven't mentioned the branch you are enquiring about. With your rank, you can easily get admission in ECE branch in LNMIIT Jaipur, while it is a little difficult for CSE as it closes at 30000.
You can use our college predictor to predict the best college for you:
Hope this answer helps you.
Good luck!!
According to the formula, [100-95*869010/100], your All India Rank is 43450 approximately, where 869010 is the total number of students who appeared in JEE Main Jan session. Since you haven't mentioned your category, I'm assuming that you are from the general category.
Now, you haven't mentioned the branch you are enquiring about. With your rank, you can easily get admission in ECE branch in LNMIIT Jaipur, while it is a little difficult for CSE as it closes at 30000.
You can use our college predictor to predict the best college for you:
Hope this answer helps you.
Good luck!!
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