chlorine is used to purify drinking water. excess of chlorine is harmful. the excess of chlorine e is removed by treating with sulphur dioxide. present a balanced equation for this redox change taking place in water.
Hello,
The reaction between chlorine and sulfur dioxide in water to remove excess chlorine is a redox reaction. Sulfur dioxide (SO2) acts as a reducing agent, reducing chlorine (Cl2) to chloride ions (Cl-), while itself being oxidized to sulfuric acid (H2SO4). The balanced equation for this reaction is:
Cl2(aq) + SO2(aq) + 2H2O(l) -> 2Cl-(aq) + H2SO4(aq)
Key points:
- Chlorine is reduced to chloride ions.
- Sulfur dioxide is oxidized to sulfuric acid.
- Occurs in aqueous solution.
Hope it helps !
Hello,
The reaction between chlorine and sulfur dioxide in water to remove excess chlorine is a redox reaction. Sulfur dioxide (SO2) acts as a reducing agent, reducing chlorine (Cl2) to chloride ions (Cl-), while itself being oxidized to sulfuric acid (H2SO4). The balanced equation for this reaction is:
Cl2(aq) + SO2(aq) + 2H2O(l) -> 2Cl-(aq) + H2SO4(aq)
Key points:
- Chlorine is reduced to chloride ions.
- Sulfur dioxide is oxidized to sulfuric acid.
- Occurs in aqueous solution.
Hope it helps !
Hello student,
The explanation for redox reaction for the removal of excess chlorine from water using sulfur dioxide (SO2) is as follows:
Explanation:
-
Chlorine (Cl2)
acts as the oxidizing agent and gets reduced to
hydrochloric acid (HCl)
.
- Sulfur dioxide (SO2) acts as the reducing agent and gets oxidized to sulfuric acid (H2SO4) .
In this reaction:
- Chlorine (Cl2) reduces from an oxidation state of +1 (in Cl2) to -1 (in HCl).
- Sulfur (S) in SO2 is oxidized from +4 to +6 (in H2SO4).
This reaction helps in removing excess chlorine and purifying the water.
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