Question : Chord AB of a circle is produced to a point P, and C is a point on the circle such that PC is a tangent to the circle. PC = 12 cm, and BP = 10 cm, then the length of AB (in m) is:
Option 1: 5.4
Option 2: 6
Option 3: 5
Option 4: 4.4
Correct Answer: 4.4
Solution :
PC=12 cm
BP=10 cm
PC
2
= AP × BP
Let AB be $x$.
AP = AB + PB = $x+10$
PC
2
= AP × BP
$12^2 = (x+10) × 10 $
⇒ $\frac{144}{10} = x + 10$
⇒ $x+10 = 14.4$
⇒ $x = 4.4$
Hence, the correct answer is 4.4.
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