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Class 10 mathematics all formulas


Satyam Saini 10th Mar, 2020
Answer (1)
Hrisheekesh Singh 10th Mar, 2020

Hi Satyam,

Here are all the formulas up to Class 10:-

  • (a+b) 2 = a 2 + b 2 + 2ab
  • (a-b) 2 = a 2 + b 2 – 2ab
  • (a+b) (a-b) = a 2 – b 2
  • (x + a)(x + b) = x 2 + (a + b)x + ab
  • (x + a)(x – b) = x 2 + (a – b)x – ab
  • (x – a)(x + b) = x 2 + (b – a)x – ab
  • (x – a)(x – b) = x 2 – (a + b)x + ab
  • (a + b) 3 = a 3 + b 3 + 3ab(a + b)
  • (a – b) 3 = a 3 – b 3 – 3ab(a – b)
  • (x + y + z) 2 = x 2 + y 2 + z 2 + 2xy + 2yz + 2xz
  • (x + y – z) 2 = x 2 + y 2 + z 2 + 2xy – 2yz – 2xz
  • (x – y + z) 2 = x 2 + y 2 + z 2 – 2xy – 2yz + 2xz
  • (x – y – z) 2 = x 2 + y 2 + z 2 – 2xy + 2yz – 2xz
  • x 3 + y 3 + z 3 – 3xyz = (x + y + z)(x2 + y2 + z2 – xy – yz -xz)
  • x 2 + y 2 =½ [(x + y) 2 + (x – y) 2 ]
  • (x + a) (x + b) (x + c) = x 3 + (a + b +c)x 2 + (ab + bc + ca)x + abc
  • x 3 + y 3 = (x + y) (x 2 – xy + y 2 )
  • x 3 – y 3 = (x – y) (x 2 + xy + y 2 )
  • x 2 + y 2 + z 2 -xy – yz – zx = ½ [(x-y) 2 + (y-z) 2 + (z-x) 2 ]
  • sin(90 ° – θ) = cos θ
  • cos(90 ° – θ) = sin θ
  • tan(90 ° – θ) = cot θ
  • cot(90 ° – θ) = tan θ
  • sec(90 ° – θ) = cosecθ
  • cosec(90 ° – θ) = secθ
  • sin 2 θ + cos 2 θ = 1
  • sec 2 θ = 1 + tan 2 θ for 0 ° ≤ θ < 90 °
  • Cosec 2 θ = 1 + cot 2 θ for 0 ° ≤ θ ≤ 90 °

Feel free to ask doubts in the Comment Section.

I hope this information helps you.

Good Luck!

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