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cos pie by 4 plus theta cos pie by 4 minus theta equal to root 2 cos theta


U.Sreenu 31st Oct, 2024
Answer (1)
Samprikta Mondal 1st Nov, 2024

The problem is thus treated in steps:


We are given that:

cos(π/4 + θ) + cos(π/4 - θ) = √2 cosθ


We shall consider the left-hand side (LHS):


The sum and difference formulas for cosine are useful here:


cos(A + B) = cosA * cosB - sinA * sinB

cos(A - B) = cosA * cosB + sinA * sinB


Substituting into our equation we get:

LHS = [cos(π/4) * cosθ - sin(π/4) * sinθ] + [cos(π/4) * cosθ + sin(π/4) * sinθ]


Now we simplify:

LHS = 2 cos(π/4) cosθ


cos(π/4) = 1/√2. Thus:

LHS = 2(1/√2) cosθ

LHS = √2 cosθ.


Hence, LHS = RHS.


So we have proved that the given equation stands correct.

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