Hi

This is very difficult to predict  cut off rank as it keeps changing every year  depending upon various factors like :-

*number of students that appeared in the exam,

*kind of marks obtained by them ,

*toughness level of the examination for different shifts

* the branch in which you want to get admission in etc.

But yes,

When we go through past year qualifying cut off trends then

The closing rank for gender neutral for computer science engineering for general category in 6th round of josaa counselling 2020  for some of the NITs is given below :-

*National Institute of Technology, Tiruchirappalli

Closing rank for computer science for general

Home state :- 4728

Open state :- 781

*National Institute of Technology Karnataka, Surathkal, 13th rank in  nirf rank 2020

Home state :-3115

Open state :-1324

* NIT Rourkela, 16th rank in  nirf rank 2020

Home state :-9816

Open state :-3296

*National Institute of Technology, Warangal , 19th rank in  nirf rank 2020

Home state :-2043

Open state :-1541

Similarly, you can get the cutoff rank for all the NITs for all the branches and JEE advanced cutoff rank for IITs as well by visiting the official page of josaa at

https://josaa.nic.in/Result/Result/currentorcr.aspx

Just copy the above link and paste on the search bar of your browser and  then search, you will get it

To predict your rank, you can use our predictor at

To have a personalised report on your chances of getting a college you can go through our college predictor, it will give you complete list of colleges which you can get on the basis of the category you belong to,  your home state, your gender etc, the link for  jee main college predictor is provided below

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

If you have any other doubt then you can always reach us to clear them :) we are always available to help you out and guide you

Thankyou