Question : DE is a chord and KDE is a secant of a circle. If KD = 9 cm, DE = 7 cm and KH is a tangent to the circle at point H, find KH.
Option 1: 12 cm
Option 2: 25 cm
Option 3: 16 cm
Option 4: 144 cm
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
Correct Answer: 12 cm
Solution :
Suppose a tangent segment and a secant segment are drawn to a circle from an exterior point. In that case, the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.
$KH^{2} = KD \times KE$
$⇒KH^{2} = 9 \times 16 = 144$ cm
$\therefore KH = 12$ cm
Hence, the correct answer is 12 cm.
Related Questions
Know More about
Staff Selection Commission Combined Grad ...
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Get Updates BrochureYour Staff Selection Commission Combined Graduate Level Exam brochure has been successfully mailed to your registered email id “”.