Question : DEF is an isosceles triangle such that DE = DF = 60 cm and EF = 96 cm. DG is a median to base EF. What is the length of DG?
Option 1: 22 cm
Option 2: 36 cm
Option 3: 24 cm
Option 4: 32 cm
Correct Answer: 36 cm
Solution :
Given:
DE = DF = 60 cm, EF = 96
DG median cuts EF into two halves.
So, EG = $\frac{96}{2}=48$ cm
In $\triangle$DEG,
DE
2
= DG
2
+ EG
2
⇒ DG = $\sqrt{60^2-48^2}=\sqrt{1296}=36$ cm
Hence, the correct answer is 36 cm.
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