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Derive the equation of ionisation constant and ionic product of water.


mindfreedomof 29th Mar, 2021
Answer (1)
Jainshahajal 29th Mar, 2021

Hello Aspirant,

DISSOCIATION CONSTANT AND IONIC PRODUCT OF WATER - DEFINITION

H2OH++OH−

This ionization is known as self-ionization of water.

Dissociation constant=K=[H2O][H+][OH−]

Ionic product of water may be defined as the product of molar concentration of H+ ions and OH− ions.

Kw=[H+][OH−]=10−14

K=55.5510−14=1.8×10−16

IONISATION OF WATER :-

The self-ionization of water (also autoionization of water, and autodissociation of water) is an ionization reaction in pure water or an aqueous solution, in which a water molecule, H2O, deprotonates (loses the nucleus of one of its hydrogen atoms) to become a hydroxide ion, OH−.
H2O→H++OH−

I hope this will help you.

Feel free to ask any query.

All the best for your bright future ahead.

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