determine dy/DX of the following 1)y=root ax +b(root is for both ax and b) 2)y=ln(2x+3) 3)y=e power 2x+3
1. y=sqrt(ax+b)
dy/dx = (a)/(2*(root(ax+b))
this is according to the chain rule.
2. y=ln(2x+3)
dy/dx=(2)/(2x+3)
this is also according to the chain rule of differentiation.
3. y=e^(2x+3)
when we apply chain rule of differentiation in this, we get:
dy/dx=(2)*(e^(2x+3))
Hope I have answered your question. All the best!