Question : Direction: Two years ago, Aadhya was three times as old as his son, and two years hence, twice her age will be equal to five times that of her son. Find Aadhya's present age.
Option 1: 38 years
Option 2: 36 years
Option 3: 34 years
Option 4: 42 years
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Correct Answer: 38 years
Solution : Let the present age of the son be x years.
Two years ago, Aadhya was three times as old as his son, the equation becomes
⇒ Aadhya's age two years ago = 3 (x – 2) = 3x – 6
⇒ Aadhya's present age = 3x – 4
Two years hence, twice her age will be equal to five times that of her son
⇒ 2 (3x – 2) = 5 (x + 2)
⇒ 6x – 4 = 5x + 10
⇒ x = 14
Aadhya's present age = 3x – 4 = (3 x 14) – 4 = 38 years.
Hence, option first is correct.
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