Question : Directions: A father's age is one more than 5 times his son's age. After 3 years, the father's age would be 2 less than four times the son's age. Find the present age of the father.
Option 1: 30 years
Option 2: 40 years
Option 3: 31 years
Option 4: 29 years
Correct Answer: 31 years
Solution : Let the present age of the father and son be F and S years respectively.
The father's present age is 1 more than 5 times his son's age ⇒ F = (5 × S) + 1
Father's age after 3 years = (5 × S) + 4
Son's age after 3 years = S + 3
After 3 years, the father's age would be 2 less than four times the son's age.
⇒ (5 × S) + 4 = 4 × (S + 3) – 2
⇒ (5 × S) + 4 = (4 × S) + 12 – 2 = (4 × S) + 10
⇒ S = 6
⇒ F = (5 × S) + 1
= 5 × 6 + 1 = 30 + 1 = 31 years.
So, the present age of the father is 31 years. Hence, the third option is correct.
Related Questions
Know More about
Staff Selection Commission Sub Inspector ...
Result | Eligibility | Application | Selection Process | Cutoff | Admit Card | Preparation Tips
Get Updates BrochureYour Staff Selection Commission Sub Inspector Exam brochure has been successfully mailed to your registered email id “”.