Question : Directions: A policeman stepped out of the police station and walked 60 m towards the west. He then took a left tum and walked 38 m to reach a fruit shop. He then took a right turn and walked 60 m. He then took a right turn and walked 38 m to reach a restaurant. What is the approximate shortest distance between the police station and the restaurant via the fruit shop?
Option 1: 71 m
Option 2: 150 m
Option 3: 112 m
Option 4: 142 m
New: SSC Stenographer Application Form 2024 Released
Don't Miss: Month-wise current affairs
Suggested: Upcoming government exams
Correct Answer: 142 m
Solution : Firstly, we will draw the diagram as per the given instructions –
Now, we have to find the shortest distance between the police station and the restaurant via the fruit shop
The approximate shortest distance between the police station and the restaurant via the fruit shop is OB + DB.
Here, OB = DB
Therefore, Distance = 2(OB)
Using the Pythagoras, we get –
(OB)
2
= (AB)
2
+ (OA)
2
(OB)
2
= (60)
2
+ (38)
2
(OB)
2
= 3600 + 1444
(OB)
2
= 5044
OB = 71.02
Now, on putting the value of OB, we get –
Distance = 2(OB) = 2 × 71.02 = 142.04 (approximately 142)
The approximate shortest distance between the police station and the restaurant via the fruit shop is 142m. Hence, the fourth option is correct.
Related Questions
Know More about
Staff Selection Commission Stenographer ...
Application | Eligibility | Dates | FAQs
Get Updates BrochureYour Staff Selection Commission Stenographer Grade C & D Exam brochure has been successfully mailed to your registered email id “”.