Correct Answer: ÷ and ×

Solution : Given:
12 × 6 – 28 + 3 ÷ 9

Replace the given symbols in the options one by one with the original symbols in the given equation.
Let's check the given options –
First Option: × and +
12 × 6 – 28 + 3 ÷ 9
= 12 + 6 – 28 × 3 ÷ 9
= 12 + 6 – 28 × 0.33
= 12 + 6 – 9.34
= 8.66 ≠ 1
Second option: + and –
12 × 6 – 28 + 3 ÷ 9
= 12 × 6 + 28 – 3 ÷ 9
= 12 × 6 + 28 – 0.33
= 72 + 28 – 0.33
= 99.67 ≠ 1
Third option: ÷ and ×
12 × 6 – 28 + 3 ÷ 9
= 12 ÷ 6 – 28 + 3 × 9
= 2 – 28 + 3 × 9
= 2 – 28 + 27
= 1
Fourth option: × and –
12 × 6 – 28 + 3 ÷ 9
= 12 – 6 × 28 + 3 ÷ 9
= 12 – 6 × 28 + 0.33
= 12 – 168 + 0.33
= –155.67 ≠ 1

So, only the third option satisfies the given equation. Hence, the third option is correct.