Question : Directions: By Interchanging the given two numbers which of the following equations will be correct?
1 and 7
Option 1: 7 × 2 + 1 – 5 = 6
Option 2: 1 × 2 – 7 + 8 ÷ 2 = 16
Option 3: 7 + 1 × 2 – 6 ÷ 3 = 13
Option 4: 7 + 6 ÷ 3 – 5 × 1 = –10
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Correct Answer: 7 + 1 × 2 – 6 ÷ 3 = 13
Solution :
Let's check the options –
First option:
7 × 2 + 1 – 5 = 6
On interchanging the given numbers, the equation becomes –
⇒ 1 × 2 + 7 – 5 = 6
Solving the L.H.S. of the equation –
= 2 + 7 – 5
= 9 – 5
= 4 ≠ 6
Second option:
1 × 2 – 7 + 8 ÷ 2 = 16
On interchanging the given numbers, the equation becomes –
⇒ 7 × 2 – 1 + 8 ÷ 2 = 16
Solving the L.H.S. of the equation –
= 7 × 2 – 1 + 4
= 14 – 1 + 4
= 17 ≠ 16
Third option:
7 + 1 × 2 – 6 ÷ 3 = 13
On interchanging the given numbers, the equation becomes –
⇒ 1 + 7 × 2 – 6 ÷ 3 = 13
Solving the L.H.S. of the equation –
= 1 + 7 × 2 – 2
= 1 + 14 – 2
= 15 – 2
= 13
Fourth option:
7 + 6 ÷ 3 – 5 × 1 = –10
On interchanging the given numbers, the equation becomes –
⇒ 1 + 6 ÷ 3 – 5 × 7 = –10
Solving the L.H.S. of the equation –
= 1 + 2 – 5 × 7
= 1 + 2 – 35
= 3 – 35
= –32 ≠ –10
So, only the equation in the third option satisfies the R.H.S. of the given equation. Hence the third option is correct.
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