Question : Directions: By Interchanging the given two numbers which of the following equations will be correct? 1 and 7
Option 1: 7 × 2 + 1 – 5 = 6
Option 2: 1 × 2 – 7 + 8 ÷ 2 = 16
Option 3: 7 + 1 × 2 – 6 ÷ 3 = 13
Option 4: 7 + 6 ÷ 3 – 5 × 1 = –10
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Correct Answer: 7 + 1 × 2 – 6 ÷ 3 = 13
Solution : Let's check the options – First option: 7 × 2 + 1 – 5 = 6 On interchanging the given numbers, the equation becomes – ⇒ 1 × 2 + 7 – 5 = 6 Solving the L.H.S. of the equation – = 2 + 7 – 5 = 9 – 5 = 4 ≠ 6 Second option: 1 × 2 – 7 + 8 ÷ 2 = 16 On interchanging the given numbers, the equation becomes – ⇒ 7 × 2 – 1 + 8 ÷ 2 = 16 Solving the L.H.S. of the equation – = 7 × 2 – 1 + 4 = 14 – 1 + 4 = 17 ≠ 16 Third option: 7 + 1 × 2 – 6 ÷ 3 = 13 On interchanging the given numbers, the equation becomes – ⇒ 1 + 7 × 2 – 6 ÷ 3 = 13 Solving the L.H.S. of the equation – = 1 + 7 × 2 – 2 = 1 + 14 – 2 = 15 – 2 = 13 Fourth option: 7 + 6 ÷ 3 – 5 × 1 = –10 On interchanging the given numbers, the equation becomes – ⇒ 1 + 6 ÷ 3 – 5 × 7 = –10 Solving the L.H.S. of the equation – = 1 + 2 – 5 × 7 = 1 + 2 – 35 = 3 – 35 = –32 ≠ –10
So, only the equation in the third option satisfies the R.H.S. of the given equation. Hence the third option is correct.
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