Question : Directions: By Interchanging the given two numbers which of the following equations will be correct? 7 and 4
Option 1: 4 – 7 + 6 ÷ 2 × 3 = 12
Option 2: 4 × 3 + 7 – 9 ÷ 3 = 20
Option 3: 7 + 4 × 2 – 6 ÷ 2 = 17
Option 4: 7 + 5 × 2 – 4 ÷ 1 = 9
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Correct Answer: 4 – 7 + 6 ÷ 2 × 3 = 12
Solution : Let's check the options – First option: 4 – 7 + 6 ÷ 2 × 3 = 12 On interchanging the numbers, we get – ⇒ 7 – 4 + 6 ÷ 2 × 3 = 12 Solving the L.H.S. of the equation – = 7 – 4 + 6 ÷ 2 × 3 = 7 – 4 + 3 × 3 = 7 – 4 + 9 = 16 – 4 = 12 Second option: 4 × 3 + 7 – 9 ÷ 3 = 20 On interchanging the numbers, we get – ⇒ 7 × 3 + 4 – 9 ÷ 3 = 20 Solving the L.H.S. of the equation – = 7 × 3 + 4 – 9 ÷ 3 = 7 × 3 + 4 – 3 = 21 + 4 – 3 = 25 – 3 = 22 ≠ 20 Third option: 7 + 4 × 2 – 6 ÷ 2 = 17 On interchanging the numbers, we get – ⇒ 4 + 7 × 2 – 6 ÷ 2 = 17 Solving the L.H.S. of the equation – = 4 + 7 × 2 – 6 ÷ 2 = 4 + 7 × 2 – 3 = 4 + 14 – 3 = 18 – 3 = 15 ≠ 17 Fourth option: 7 + 5 × 2 – 4 ÷ 1 = 9 On interchanging the numbers, we get – ⇒ 4 + 5 × 2 – 7 ÷ 1 = 9 Solving the L.H.S. of the equation – = 4 + 5 × 2 – 7 ÷ 1 = 4 + 5 × 2 – 7 = 4 + 10 – 7 = 14 – 7 = 7 ≠ 9
So, only the first option satisfies the given equation. Hence, the first option is correct.
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