Question : Directions: By interchanging the given two signs and numbers which of the following equations will be correct? + and –, 7 and 6
Option 1: 4 × 7 + 6 – 3 ÷ 1 = 20
Option 2: 8 × 7 + 5 ÷ 1 – 6 = 17
Option 3: 7 – 6 × 3 + 4 ÷ 1 = 8
Option 4: 7 × 2 – 6 + 4 ÷ 2 = 13
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Correct Answer: 4 × 7 + 6 – 3 ÷ 1 = 20
Solution : Let's check the options – First option: 4 × 7 + 6 – 3 ÷ 1 = 20 On interchanging the given numbers and signs, the equation becomes – ⇒ 4 × 6 – 7 + 3 ÷ 1 = 20 Solving the L.H.S. of the equation – = 4 × 6 – 7 + 3 = 24 – 7 + 3 = 20 Second option: 8 × 7 + 5 ÷ 1 – 6 = 17 On interchanging the given numbers and signs, the equation becomes – ⇒ 8 × 6 – 5 ÷ 1 + 7 = 17 Solving the L.H.S. of the equation – = 8 × 6 – 5 + 7 = 48 – 5 + 7 = 50 ≠ 17 Third option: 7 – 6 × 3 + 4 ÷ 1 = 8 On interchanging the given numbers and signs, the equation becomes – ⇒ 6 + 7 × 3 – 4 ÷ 1 = 8 Solving the L.H.S. of the equation – = 6 + 7 × 3 – 4 = 6 + 21 – 4 = 23 ≠ 8 Fourth option: 7 × 2 – 6 + 4 ÷ 2 = 13 On interchanging the given numbers and signs, the equation becomes – ⇒ 6 × 2 + 7 – 4 ÷ 2 = 13 Solving the L.H.S. of the equation – = 6 × 2 + 7 – 2 = 12 + 7 – 2 = 17 ≠ 13
So, only the equation in the first option satisfies the R.H.S. of the given equation. Hence the first option is correct.
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