Question : Directions: By interchanging the given two signs which of the following equations will be correct?
+ and –
Option 1: 55 ÷ 11 – 15 + 3 × 2 = 15
Option 2: 4 × 3 – 6 ÷ 2 + 7 = 7
Option 3: 15 – 7 × 8 + 18 ÷ 3 = 65
Option 4: 529 ÷ 23 + 10 – 5 × 4 = 30
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Correct Answer: 15 – 7 × 8 + 18 ÷ 3 = 65
Solution :
Let's check the options –
First option:
55 ÷ 11 – 15 + 3 × 2 = 15
On interchanging the given signs, the equation becomes –
⇒ 55 ÷ 11 + 15 – 3 × 2 = 15
Solving the L.H.S. of the equation –
= 5 + 15 – 3 × 2
= 5 + 15 – 6
= 14 ≠ 15
Second option:
4 × 3 – 6 ÷ 2 + 7 = 7
On interchanging the given signs, the equation becomes –
⇒ 4 × 3 + 6 ÷ 2 – 7 = 7
Solving the L.H.S. of the equation –
= 4 × 3 + 3 – 7
= 12 + 3 – 7
= 8 ≠ 7
Third option:
15 – 7 × 8 + 18 ÷ 3 = 65
On interchanging the given signs, the equation becomes –
⇒ 15 + 7 × 8 – 18 ÷ 3 = 65
Solving the L.H.S. of the equation –
= 15 + 7 × 8 – 6
= 15 + 56 – 6
= 65
Fourth option:
529 ÷ 23 + 10 – 5 × 4 = 30
On interchanging the given signs, the equation becomes –
⇒ 529 ÷ 23 – 10 + 5 × 4 = 30
Solving the L.H.S. of the equation –
= 23 – 10 + 5 × 4
= 23 – 10 + 20
= 33 ≠ 30
So, only the equation in the third option satisfies the R.H.S. of the given equation. Hence the third option is correct.
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