Question : Directions: Choose one of the following correct combinations of mathematical signs that can be filled to balance the following equation.
86 * 42 * 12 * 3 * 12 * 3 * 4
Option 1: +, –, ÷, ×, =, +
Option 2: –, –, ÷, =, ×, +
Option 3: –, +, ÷, ×, =, +
Option 4: –, +, ×, =, ÷, +
Correct Answer: –, –, ÷, =, ×, +
Solution :
Given:
86 * 42 * 12 * 3 * 12 * 3 * 4
Let's check each option –
First option:
+, –, ÷, ×, =, +
86 + 42 – 12 ÷ 3 × 12 = 3 + 4
L.H.S. = 86 + 42 – 12 ÷ 3 × 12
=
86 + 42 – 4 × 12
=
86 + 42 – 48
= 80
R.H.S. = 3 + 4 = 7
L.H.S. ≠ R.H.S.
Second option:
–, –, ÷, =, ×, +
86 – 42 – 12 ÷ 3 = 12 × 3 + 4
L.H.S. = 86 – 42 – 12 ÷ 3
= 86 – 42 – 4
= 40
R.H.S. = 12 × 3 + 4 = 36 + 4 = 40
L.H.S. = R.H.S.
Third option:
–, +, ÷, ×, =, +
86 – 42 + 12 ÷ 3 × 12 = 3 + 4
L.H.S. =
86 – 42 + 12 ÷ 3 × 12
= 86 – 42 + 4 × 12
= 86 – 42 + 48
= 92
R.H.S. =
3 + 4 = 7
L.H.S. ≠ R.H.S.
Fourth option:
–, +, ×, =, ÷, +
86 – 42 + 12 × 3 = 12 ÷ 3 + 4
L.H.S. = 86 – 42 + 12 × 3
= 86 – 42 + 36
= 80
R.H.S. = 12 ÷ 3 + 4 = 4 + 4 = 8
L.H.S. ≠ R.H.S.
So, only the second option satisfies the R.H.S. of the given equation. Hence, the second option is correct.
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