Question : Directions: Choose one of the following correct combinations of mathematical signs that can be filled to balance the following equation. 86 * 42 * 12 * 3 * 12 * 3 * 4
Option 1: +, –, ÷, ×, =, +
Option 2: –, –, ÷, =, ×, +
Option 3: –, +, ÷, ×, =, +
Option 4: –, +, ×, =, ÷, +
Correct Answer: –, –, ÷, =, ×, +
Solution : Given: 86 * 42 * 12 * 3 * 12 * 3 * 4
Let's check each option – First option: +, –, ÷, ×, =, + 86 + 42 – 12 ÷ 3 × 12 = 3 + 4 L.H.S. = 86 + 42 – 12 ÷ 3 × 12 = 86 + 42 – 4 × 12 = 86 + 42 – 48 = 80 R.H.S. = 3 + 4 = 7 L.H.S. ≠ R.H.S. Second option: –, –, ÷, =, ×, + 86 – 42 – 12 ÷ 3 = 12 × 3 + 4 L.H.S. = 86 – 42 – 12 ÷ 3 = 86 – 42 – 4 = 40 R.H.S. = 12 × 3 + 4 = 36 + 4 = 40 L.H.S. = R.H.S. Third option: –, +, ÷, ×, =, + 86 – 42 + 12 ÷ 3 × 12 = 3 + 4 L.H.S. = 86 – 42 + 12 ÷ 3 × 12 = 86 – 42 + 4 × 12 = 86 – 42 + 48 = 92 R.H.S. = 3 + 4 = 7 L.H.S. ≠ R.H.S. Fourth option: –, +, ×, =, ÷, + 86 – 42 + 12 × 3 = 12 ÷ 3 + 4 L.H.S. = 86 – 42 + 12 × 3 = 86 – 42 + 36 = 80 R.H.S. = 12 ÷ 3 + 4 = 4 + 4 = 8 L.H.S. ≠ R.H.S.
So, only the second option satisfies the R.H.S. of the given equation. Hence, the second option is correct.
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