Correct Answer: Tuesday

Solution : Given:
18th October 2006 =  Wednesday.

In a normal year, we have one odd day; in a leap year, we have two odd days. So, the total odd days –
18th October 2000 to 18th October 2001→1 odd day
18th October 2001 to 18th October 2002→1 odd day
18th October 2002 to 18th October 2003→1 odd day
18th October 2003 to 18th October 2004→2 odd day
18th October 2004 to 18th October 2005→1 odd day
18th October 2005 to 18th October 2006→1 odd day
So the number of odd days is 7, which can be divided completely by 7. Therefore, we can conclude that October 18th, 2000 was also a Wednesday, and the previous day before it was a Tuesday.

So, the day of the week on 17th October 2000 is Tuesday. Hence, the first option is correct.