Question : Directions: In a certain code language, ABKN is coded as 84, and PNCL is coded as 135. How will HONT be coded in that language?
Option 1: 181
Option 2: 171
Option 3: 169
Option 4: 147
Correct Answer: 171
Solution :
Given:
ABKN is coded as 84, and PNCL is coded as 135.
The sum of the place values of the letters of the letter clusters ABKN and PNCL is multiplied by 3 to obtain the required code.
ABKN→1 + 2 + 11 + 14 = 28; 28 × 3 = 84
Thus, ABKN is written as 84.
PNCL→16 + 14 + 3 + 12 = 45; 45 × 3 = 135
Thus, PNCL is written as 135.
Similarly, HONT→8 + 15 + 14 + 20 = 57; 57 × 3 = 171
So, HONT is coded as 171. Hence, the second option is correct.
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