Question : Directions: In a certain code language, RA + FE is coded as 246, and AB + JC is coded as 115. How will AC + BD be coded in that language?
Option 1: 39
Option 2: 23
Option 3: 27
Option 4: 37
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Correct Answer: 37
Solution : Given: RA + FE is coded as 246, and AB + JC is coded as 115.
Write down the positional values of the alphabet of RA + FE combine the values of the alphabet as shown below and then add the values to obtain the required code – R(18)A(1) + F(6)E(5)→181 + 65 = 246 A(1)B(2) + J(10)C(3)→12 + 103 = 115 Similarly, A(1)C(3) + B(2)D(4) = 13 + 24 = 37
So, AC + BD is coded as 37. Hence, the fourth option is correct.
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