Correct Answer: 4

Solution : Given:
ROUTE is coded as 7, and SHARE is coded as 6.

Determine the sum of the digits of the sum of the positional value of ROUTE to obtain the required code –
Positional values of letters of ROUTE
R→18; O→15; U→21; T→20; E→5
18 + 15 + 21 + 20 + 5 = 79
Sum of digits (79) = 7 + 9 = 16→1 + 6 = 7
Thus, ROUTE is coded as 7.
And, SHARE is coded as 6 –
Position values of letters of SHARE
S→19; H→8; A→1; R→18; E→5
19 + 8 + 1 + 18 + 5 = 51
Sum of digits (51) = 5 + 1 = 6
Thus, SHARE is coded as 6.
Similarly, follow the same pattern for TABLE –
Positional value of letters of TABLE
T→20; A→1; B→2; L→12; E→5
20 + 1 + 2 + 12 + 5 = 40
Sum of digits (40) = 4 + 0 = 4

Thus, TABLE is coded as 4. Hence, the second option is correct.