Question : Directions: In a group of 50 students, 25 play Hockey, 30 play Football, and 8 play no games. What is the number of students who play both Hockey and Football?
Option 1: 10
Option 2: 11
Option 3: 12
Option 4: 13
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Correct Answer: 13
Solution : Given: Total number of students = 50 Number of students who play hockey = 25 Number of students who play football = 30 Number of students who play neither sport = 8
Let the number of students that participate in both football and hockey = a. ⇒ 50 = 25 + 30 – a + 8 ⇒ 50 = 55 – a + 8 ⇒ a = 55 + 8 – 50 ⇒ a = 63 – 50 = 13
So, 13 students play both football and hockey. Hence, the fourth option is correct.
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Question : Directions: Which of the following interchanges of signs and numbers would make the given equation correct? 25 – 10 ÷ 5 + 15 × 30 = 55
Question : Directions: If 11 & 25 = 18, 12 & 20 = 16 then, what is the value of 4 & 50 = ?
Question : Directions: By interchanging the given two signs which of the following equations will not be correct? – and ÷
Question : Directions: Which of the following interchanges of numbers would make the given equation correct? 7 × 4 ÷ 14 + 12 + 30 = 50
Question : Directions: Which of the following interchange of numbers and mathematical signs would make the given equation correct? 30 ÷ 6 × 4 + 15 − 35 = 25
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