Question : Directions: In the following question, a series is given with one (or more) number(s)/alphabet missing. Choose the correct alternative from the given options.
J2Z, K4X, L7V, M11T, ?
Option 1: O17R
Option 2: N17S
Option 3: R16N
Option 4: N16R
Correct Answer: N16R
Solution :
Given:
J2Z, K4X, L7V, M11T, ?
Add 1 to the place value of the first letter and add consecutive natural numbers starting from 2 to the number of the previous term respectively, and subtract 2 from the third letter to obtain the next term in the series –
J2Z→J + 1 = K; 2 + 2 = 4; Z – 2 = X→K4X
K4X→K + 1 = L; 4 + 3 = 7; X – 2 = V→L7V
L7V→L + 1 = M; 7 + 4 = 11; V – 2 = T→M11T
M11T→M + 1 = N; 11 + 5 = 16; T – 2 = R→N16R
So, N16R is the missing term of the series. Hence, the fourth option is correct.
Related Questions
Know More about
Staff Selection Commission Sub Inspector ...
Result | Eligibility | Application | Selection Process | Cutoff | Admit Card | Preparation Tips
Get Updates Brochure
Your Staff Selection Commission Sub Inspector Exam brochure has been successfully mailed to your registered email id “”.
