Question : Directions: In the following question, a series is given with one (or more) number(s)/alphabet missing. Choose the correct alternative from the given options.
J2Z, K4X, L7V, M11T, ?

Option 1: O17R

Option 2: N17S

Option 3: R16N

Option 4: N16R


Team Careers360 24th Jan, 2024
Answer (1)
Team Careers360 25th Jan, 2024

Correct Answer: N16R


Solution : Given:
J2Z, K4X, L7V, M11T, ?

Add 1 to the place value of the first letter and add consecutive natural numbers starting from 2 to the number of the previous term respectively, and subtract 2 from the third letter to obtain the next term in the series –
J2Z→J + 1 = K; 2 + 2 = 4; Z – 2 = X→K4X
K4X→K + 1 = L; 4 + 3 = 7; X – 2 = V→L7V
L7V→L + 1 = M; 7 + 4 = 11; V – 2 = T→M11T
M11T→M + 1 = N; 11 + 5 = 16; T – 2 = R→N16R

So, N16R is the missing term of the series. Hence, the fourth option is correct.

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