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Question : Directions: In the following question, find the odd letter cluster from the given alternatives. 

Option 1: AKWE

Option 2: PNTO

Option 3: LCUF

Option 4: JHMX


Team Careers360 2nd Jan, 2024
Answer (1)
Team Careers360 14th Jan, 2024

Correct Answer: JHMX


Solution : Let's check the options–
First option: AKWE; The vowels A and E are present in the letter cluster.
Second option: PNTO; The vowel O is present in the letter cluster.
Third option: LCUF; The vowel U is present in the letter cluster.
Fourth option: JHMX; There is no vowel present in the letter cluster.

So, all the options have at least 1 vowel except the fourth option. Hence, the fourth option is correct.

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