Question : Directions: In the following question, find the odd letter cluster from the given alternatives.
Option 1: AKWE
Option 2: PNTO
Option 3: LCUF
Option 4: JHMX
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Correct Answer: JHMX
Solution :
Let's check the options–
First option:
AKWE; The vowels A and E are present in the letter cluster.
Second option:
PNTO; The vowel O is present in the letter cluster.
Third option:
LCUF; The vowel U is present in the letter cluster.
Fourth option:
JHMX; There is no vowel present in the letter cluster.
So, all the options have at least 1 vowel except the fourth option. Hence, the fourth option is correct.
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