Question : Directions: In the following question, find the odd letter cluster from the given alternatives.
Option 1: AEFJ
Option 2: KOPT
Option 3: UYZD
Option 4: EHIL
Correct Answer: EHIL
Solution :
Let's check the options –
First option:
AEFJ; A + 4 = E; E + 1 = F; F + 4 = J
Second option:
KOPT; K + 4 = O; O + 1 = P; P + 4 = T
Third option:
UYZD; U + 4 = Y; Y + 1 = Z; Z + 4 = D
Fourth option:
EHIL; E + 3 = H; H + 1 = I; I + 3 = L
So, the fourth option is different from the other three options because the difference in the position value of the letters is different. Hence, the fourth option is correct.
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