Question : Directions: In the following question, find the odd letter cluster from the given alternatives.
Option 1: SU
Option 2: BD
Option 3: IK
Option 4: PN
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Correct Answer: PN
Solution : Let's check the options –
First option:
SU; S + 2 = U
Second option:
BD; B + 2 = D
Third option:
IK; I + 2 = K
Fourth option:
PN; P – 2 = N
So, the fourth option is different from the other three options because the difference in the position value of the letters is –2 instead of +2. Hence, the fourth option is correct.
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