Question : Directions: In the following question, find the odd sequence of numbers from the given alternatives.
Option 1: 1, 2, 4, 8
Option 2: 2, 6, 10, 14
Option 3: 3, 9, 15, 21
Option 4: 7, 21, 35, 49
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Correct Answer: 1, 2, 4, 8
Solution : Let's check the options – First option: 1, 2, 4, 8; 1 × 2 = 2; 1 × 4 = 4; 1 × 8 = 8 Second option: 2, 6, 10, 14; 2 × 3 = 6; 2 × 5 = 10; 2 × 7 = 14 Third option: 3, 9, 15, 21; 3 × 3 = 9; 3 × 5 = 15; 3 × 7 = 21 Fourth option: 7, 21, 35, 49; 7 × 3 = 21; 7 × 5 = 35; 7 × 7 = 49
So, the first option is different from the other three options as it does not have the third, fifth, and seventh multiples of the first number of the group. Hence, the first option is correct.
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Question : Directions: How many 8's followed by an even number and preceded by an odd number? 7, 8, 5, 6, 7, 8, 4, 3, 2, 1, 3, 8, 6, 4, 3, 7, 8, 4, 2, 1, 3, 8, 2, 8, 9
Question : If $A:B=7:9$ and $B:C =3:5$, then $A:B:C$ is equal to:
Question : Directions: In the following question, select the one which is different from the other three alternatives.
Question : If A : B = 2 : 3, B : C = 6 : 7, C : D = 14 : 3, then find A : B : C : D.
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